1260 1290 1335 37 185 matrix plus 3d matrix

1 + 1 + 1 = 3

2 + 2 + 3 = 7

6 + 9 + 3 = 18

0 + 0 + 5 = 5

So…

3. 7. 18. 5 Or

37,185

This is very reminiscent of:-

2300-1335-noah-and-assyrian-siege/

………

Ok, let’s now do a 3d matrix. So, we take the 2d matrix from above but repeat the 2d matrix so that there are 4 2d (dimensional) matrices thus making a 3d object.

Now we take the 2d matrix result, 37,185 and multiply by 4

37,185 × 4 = 148,740

Now, let’s digit group this result…

148 and 740

148 + 740 = 888

888. That’s… Jesus

Pretty good.

Let’s do some more matrices.

37,185 × 2 = 74,370

74 + 370 = 444

37,185 × 3 = 111,556

111 + 555 = 666

37,185 × 4 = 148,740

148 + 740 = 888

37,185 × 5 = 185,925

185 + 925 = 1,110

37,185 × 6 = 223,110

223 + 110 = 333

37,185 × 7 = 260,295

260 + 295 = 555

37,185 × 8 = 297,480

297 + 480 = 777

And so on…😂

1260 1290 1335 … 777 Riddle

3885 ÷ 37 = 105 = 7 × 15

15 is the highest common factor of the 3 day numbers…

1260 ÷ 15 = 84

1290 ÷ 15 = 86

1335 ÷ 15 = 89

84 + 86 + 89 = 259

(3885 ÷ 15 = 259)

259 ÷ 37 = 7

3 × 259 = 777 (= 3 × 7 × 37)

…………

1260 + 1290 + 1335 = 3885

Now, digit group, so…

3 + 885 = 888

…….

1260:-

Rev 12:6: “and the woman fled into the wilderness, where she has a place prepared by God, in which she is to be nourished for 1,260 days.”

Yup, it’s chapter and verse, Rev 12:6,you just have to add the “0”. It’s staring you in the face 😀.